Tiny House Experiments SMC

Thermal Mass

Specific Heat Capacity - Water

The specific heat capacity of water in SI units is approximately 4.184 joules per gram per degree Celsius (J/g°C) or equivalently 4,184 joules per kilogram per degree Celsius (J/kg°C). This means it takes 4.184 joules of energy to raise the temperature of 1 gram of water by 1 degree Celsius or 1 kilogram of water by 1 degree Celsius.

how much energy would it take to raise the temperature of 2L of water from 15degC to 25degC. Express energy in Joules and also in Watts or Watt hours

To calculate the energy required to raise the temperature of 2 liters (or 2,000 grams) of water from 15°C to 25°C, you can use the specific heat capacity of water (4.184 J/g°C). The formula to calculate energy (Q) is:

Q=m⋅c⋅ΔT

Where:

• Q is the energy in joules.
• m is the mass of the water in grams (2,000 grams in this case).
• c is the specific heat capacity of water (4.184 J/g°C).
• ΔT is the change in temperature in degrees Celsius (25°C - 15°C = 10°C).

Now, plug in the values and calculate:

Q=2,000g⋅4.184J/g°C⋅10°C=83,680J

So, it would take 83,680 joules of energy to raise the temperature of 2 liters of water from 15°C to 25°C.

1 Watt = 1 J/s

If it took 1 hour to raise the temperature we can calculate that Watts input

83,680 / (3600 seconds in an hour) = 23 Watt.hours (23 Watts for 1 hour)

Energy entering Tiny House from Environemnt at 40degC

Watts = Area x ΔT x 1/R

Watts = (0.4 x 0.4 x 6) x (40-20degC) x 1/4

= 0.96m2 x 20degC x 1/ (4 m²K/W) = 4.8 Watts on a 40degC Day